CS502 Final Term Solved MCQs Set 2 by Junaid
- Type
- Final term past paper
- Course
- CS502 Fundamentals of Algorithms
- Size
- PDF 3.3 MB
- Updated
- 23 Oct 2026
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Text from pages 2, 3, 4 of 104. Download the file for all 104 pages.
Q1. Which method is preferable for dealing with chain matrix multiplication?
Divide and conquer strategy
Dynamic programming formulation
Graph theory
Greedy Approach
- Huffman algorithm produces the…….prefix code tree.
Better
Optimal
Worst
Best
- A….w is adjacent to vertex v if there is an edge from v to w.
Acyclic
Vertex
Loop
Cycle
4. Using ASCII standard the string “greedy” will be encoded with
i. 44 bits
ii. 120 bits
iii. 40 bits
iv.
48 bits
5. Find the maximum value of the items which can carry using knapsack weight capacity
=50
Item weight Value
i.
ii.
iii.
iv.
6. In activity scheduling algorithm, each activity is represented by a
i.
Rectangle
ii. Square i. Searching
ii. Sorting
iii. Linear solution
iv.
Optimization
9. The general coin change problem can be solved using
i. Recursion
ii. Greedy algorithm
iii.
iv.
10. Huffman algorithm produces the................ prefix code tree
i.
Optimal
ii. Better
iii. Best
iv. Worst
11. Huffman algorithm generates an optimum .......code
i. Postfix
ii. Infix
iii. None of the given options
iv.
Prefix
12 ....... ways of representing graphics
i.
ii.
iii.
iv.
13. Knapsack word originates from ……language
i.
German
ii. English
iii. French
iv. Norwegian iii. Circle
iv. Triangle
- Those problems in which greedy finds good, but not always best is called a greedy…..
i.
Heuristic
ii. Solution
iii. Result
iv. Algorithm
8. The knapsack problem belongs to the domain of…..Problems
14. Graphs are important ........ model for many application problems
i.
Mathematical
ii. Unpredictable
iii. Haphazard
iv. Unsystematic
Q15. Which type of algorithm is harder to prove the correctness?
i. Dynamic i. Nether commutative nor associative
ii. Transitive
iii. Commutative
iv.
Associative
18. For a Diagraph G= (V.E), Sum of in-degree (v) ----------------- --.
Not equal to sum of out-degree(v)
= sum of out-degree(v) pg#115
< sum of out-degree(v)
> sum of out-degree(v)
- DFS or BFS yields a ------------- of the graph.
Traversed tree
Spanning tree pg#125
Simple tree
Free tree
- Using ASCII code, each character is represented by a fixed-length code of ------------- bits per
character. ii. Greedy
iii.
iv. Brute force
16 ....... Items are not allowed in 0/1 knapsack problem
i. Fractional
ii.
iii.
iv.
17. Matrix multiplication is a(n) ......... operation
21. In Knapsack Problem, the goal is to put items in the Knapsack
such that the value of the items is---------
-------subject to weight limit of the Knapsack. 8 pg#100
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