MTH202 Midterm Solved Subjective Papers with References
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- Midterm past paper
- Course
- MTH202 Discrete Mathematics
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- PDF 243 KB
- Updated
- 23 Oct 2026
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Math202 Midterm Subjective Paper
• Q: Suppose that a connected planar simple graph has 15 edges. If a plane drawing of this graph has 7 faces, how many vertices does this graph have?
Answer: Given, Edges = v =15 Faces = f = 7 Vertices = v =? According to Euler Formula, we know that, f= e – v +2 Putting values, we get 7 = 15 – v + 2 7 = 17 – v Simplifying v =1 7-7 =10
• Q: How many ordered selections of two elements can be made from the set {0,1,2,3}?
Answer: The order selection of two elements from 4 is as P(4,2) = 4!/(4-2)! = (4.3.2.1)/2! = 12
- Q: Find a non-isomorphic tree with five vertices.
Answer: There are three non-isomorphic trees with five vertices as shown (where every tree with five vertices has 5-1=4 edges).
• Q: Define a predicate?
Answer: Let the declarative statement: “x is greater than 3”. We denote this declarative statement by P(x) where x is the variable, P is the predicate “is greater than 3”. The declarative statement P(x) is said to be the value of the propositional function P at x.
- Q: There are 25 people who work in an office together. Four of these people are selected to attend four different conferences. The first person selected will go to a conference in New York, the second will go to Chicago, the third to San Francisco, and the fourth to Miami. How many such selections are possible?
- Ans = 12650
• Q: Prove that every integer is a rational number?
Answer: Every integer is a rational number, since each integer n can be written in the form n/1. For example 5 = 5/1 and thus 5 is a rational number. However, numbers like 1/2, 45454737/2424242, and -3/7 are also rational; since they are fractions whose numerator and denominator are integers.
- Q: Draw a graph with six vertices, five edges that is not a tree.
Answer: Here is the graph with six vertices, five edges that is not a tree Q: Let A
and B be events with P (A) = ½ , P(B)=1/3 and P (A ∩B) = ¼ Find P (B|A) Ans
= P(A ∩ B) = P(A) P(B|A) P(B|A)= P(A ∩ B)/ P(A) = 0.5
• Q: What are Complementary Graphs?
Answer: Complementary Graph of a simple graph(G) is denoted by the (G bar ) and has as many vertices as G but two vertices are adjacent in complementary Graph by an edge if and only if these two vertices are not adjacent in G .
• Q: What is chromatic number?
Answer: While coloring a graph you can color a vertex which is choosing a new color for it or by the same color which you have used for the vertices which are not adjacent with this vertex. It means that while coloring a graph you may have different number of colors used for this purpose. But the least number of colors which are being used during the coloring of Graphs is known as the Chromatic number
• Q: What is Tauology?
- A: A tautology is a statement form that is always true regardless of the truth values of the statement variables. i.e. If you want to prove that (p v q) is tautology, you have to show that all values of statement (p v q) are true regardless of the values of p and q.If all the values of the statement (p v q) is not true then this statement is not tautology.
• Q: what is the basic difference b/w sequences and series
Answer: A sequence is just a list of elements .In sequence we write the terms of sequence as a list (separated by comma's). e.g 2,3,4,5,6,7,8,9,... ( in this we have terms 2,3,4,5,6,7,8,9 and so on).we write these in form of list separated by comma's. And the sum of the terms of a sequence forms a series. e.g we have sequence 1,2,3,4,5,6,7 Now the series is sum of terms of sequence as 1+2+3+4+5+6+7.
• Q: How to use conditional probability
Answer: Dear student In Conditional probability we put some condition on an event to be occur. e.g. A pair of dice is tossed. Find the probability that one of the dice is 2 if the sum is 6. If we have to find the probability that one of the dice is 2, then it is the case of simple probability. Here we put a condition that sum is six. Now A = { 2 appears in at least one die} E = {sum is 6 } Here E = { (1,5), (2, 4), (3, 3), (4, 2), (5, 1) } Here two order pairs ( 2, 4 ) and ( 4, 2) satisfies the A. (i.e. belongs to A) Now A (intersection) B= { (2,4), (4,2)} Now by formula P(A/E) = P(A (intersection) E)/ P(E) = 2/5
- Question: What is the difference between yes and allowed in graphs.
Answer: Allowed mean that specific property can be occurs in that case but yes mean that specific property always occurs in that case. e.g. In Walk you may start and end at same point and may not be (allowed). But in Closed Walk you have to start and end at same point (yes).
- Q: What is improper subset.
Answer: Let A and B be sets. A is proper subset of B, if, and only if, every element of A is in B but there is at least on element if B that is not in A. Now A is improper subset of B, if and only if, every element of A is in B and there is no element in B which is not in A. e.g. A= { 1, 2 , 3, 4} B= { 2, 1, 4, 3} Now A is improper subset of B. Because every element of A is in B and there is no element in B which is not in A
• Q: Is Pie an irrational number?
Answer: Pi π is an irrational number as its exact value has an infinite decimal expansion: Its decimal expansion never ends and does not repeat. The numerical value of π truncated to 50 decimal places is:3.14159 26535 89793
- Q: How empty set become a subset of every set.
Answer: If A & B are two sets, A is called a subset of B, if, and only if, every element of A is also an element of B. Now we prove that empty set is subset of any other set by a contra positive statement( of above statement) i.e. If there is any element in the the set A that is not in the set B then A is not a subset of B. Now if A={} and B={1,3,4,5} Then you cannot find an element which is in A but not in B. So A is subset of B.
a set a=(1,2,3) and relation was given and we have to find R(bar
Answer: (p ∨ q) ∧ (∼p ∨ ~q)
Answer: Conjunction
Q.No 1
A circuit with two input signals and one output signal is called
The statement “It is not raining if and only if roads are dry” is logically equivalent to
If roads are dry then it is not raining.
Roads are dry if and only if it is not raining
If it is not raining then roads are dry
None Of these.
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