- Type
- Quiz
- Course
- MTH202 Discrete Mathematics
- Size
- PDF 205 KB
- Updated
- 23 Oct 2026
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Text from pages 1, 2, 3 of 4. Download the file for all 4 pages.
Q1. Solution:
A B A-B
Hence, proves that L.H.S=R.H.S
Q2. Using a truth table, determine whether the following statement is a tautology or a contradiction ?
(p ∧ q) ∨ (∼p ∨ (p ∧ ∼q))
Solution:
p q ∼p ∼q p ∧ ∼q ∼p ∨ (p ∧ ∼q) p ∧ q (p ∧ q) ∨ (∼p ∨ (p ∧ ∼q))
T T F F F F T T
T F F T T T F T
F T T F F T F T
F F T T F T F T
The given statement is Tautology.
Q3. Construct a truth table of the following statement.
(p ∨ q) ∨ (∼p ∧ q) → q
Solution:
The truth table is given below:
p q p ∨ q ∼p ∼p ∧ q (p ∨ q) ∨ (∼p ∧ q) (p ∨ q) ∨ (∼p ∧ q) → q
T T T F F F T
T F T F F F T F T T T T F T
F F F T F F T
Q4. Using truth table, determine the validity of the argument.
p q r ∼q ∼r p ∧ q p ∧ q → ∼r p ∨ ∼q ∼q → p ∼r
T T T F F T F T T F T T F F T T T T T T T F T T F F T T T F T F F T T F T T T T F T T F F F T F T F F T F F T F T F T T F F T T F F T T F F F F F T T F T T F T
Arguments of row 2 and row 4 are valid because the conclusion is true when all the premises are true.
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