- Type
- Midterm past paper
- Course
- MTH401 Differential Equations
- Size
- PDF 324 KB
- Updated
- 23 Oct 2026
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- The Time allowed for this paper is 60 minutes.
- This examination is closed book, closed notes, closed neighbors; any one found cheating will get zero grades in
the course MTH401 Differential Equations.
- You are not allowed to use any type of Table for Formulae of Differentiation and integration during your exam.
- Each objective type question carries 2 marks and each Descriptive question carries 10 marks. So write every
step of the solution of descriptive question to get maximum marks.
Q1. Marks: 2
dy − y
e y
is x
not Bernoulli equation. dx The differential equation
T
F
Marks: 2
Q2. x
fxy
x
Is homogeneous.
T
F
Q3. Population dynamics are not practical application of the first order differential
equations.
T
F
Q4. A set
1, n yy
I n
linearly dependent solutions, on
interval a n x d n y
n dx x a n d n
1 − dx n Of n
th-order differential
equation , of the homogeneous
linear x dy
dx a x y a y L
I
Is said to be a fundamental set of solutions on the
inte l rva T
F
Q5. x
2x D
The differential operator that
ann ilates ih
T
is
F
Q6. r
r d r r r d θ θ θ θ θ
(a)
Define separable form. Just separate the variables of the given differential
equation.
Solution
Q The differential equation of the form d y / d x = f (x, y) is called
d y / d x = h(x)g(y) separable if it can be written in the form
r − θ θ r − dr − r θ θ r − d θ
r − θ θ r − dr r θ θ r − d θ
1) 3 θ (
- 1( 1( 2)
r −− r dr r − r θ d
r θ d r r θ θ
dr
θ θ
d θ d θ
r
r
Q6. Question No: 6
Marks:10
(b) Check whether the given differential equation is exact or not if not then make it exact also show that it is
exact (
x d y x
d x
Solution
It can also be written as xdx x dy
x N , xy 2 − x M xy ,
0,
x M ≠ N x M N x
Thus it is not exact now we apply techniques to make it exact
xdx y − x dy
x N M x
M x gy
dy IF e − ∫
e
− dx e − y − x dy 0 xe
M xy xe − N xy e − x
x N − x − e M e x
M
x N
Which shows that equation is exact
Q7. dy
x
dx xy
(a)
Solve the Bernoulli equation
dy
x
dx x y
dy y
dx x x
put y v
dy dv
dx dx
dy dv
y −
dx dx
Then
dv v
dx x x 3
dv v
dx x x
Thus it is linear in “v”.
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