PHY101 Midterm Past Papers

Q1. The lowest tone produced by a certain organ comes from a 3.0-m pipe with both ends open. If the speed of sound is 340m/s, the frequency of this tone is approximately: (1 marks)

1. A. 7Hz
2. B. 14 Hz
3. C. 28 Hz
4. D. 57 Hz page no 53

Reference:-

According to handouts t=wavelength/v · And as we know we want to find frequency · There we made some changes In this equation · 1/t=v/wavelength · As 1/t=f so · F=v/wavelength · Note:- · All Midterm solved MCQZ (With · reference) and related subjective of

PHY101.

And all 1 to 22 chapters formulas in

easy format.

The subjective questions are from past · papers and some are for · Exercise. Normally the paper of Physics · is Conceptual paper So this is not · guarantee that material will come from

this file or any other past paper.

This is just for exercise and gives you

idea to solve numerical and objective. Anyhow best of luck for Papers.

R · b · i · Th · k

And we know that wavelength for an open ended pipe is 2L which is now 6 m

F=340/6 = 56.6 which is approximately equal to 57.

Q2. 1. To raise the pitch of a certain piano string, the piano tuner: (1 marks)

1. A. loosens the string
2. B. tightens the string
3. C. shortens the string page no 54
4. D. lengthens the string

Reference:-

Hnmm look at this line given in handouts on page 54

“So as the observer runs towards the source, she hears a higher frequency

Higher pitch)”

Means to say jitna hum source k kareeb jate jain gin distance kam hota jay ga

Orr utni hi ziada frequency ya pitch sunai de gi isi tra jitna piano k string ko kam Karin gin utni ziada pitch produce hogi.

Q3. A force of 5000N is applied outwardly to each end of a 5.0-m long rod with a radius of (1 marks)

Q34. 0 cm and a Young's modulus of 125 × 108 N/m2. The elongation of the rod is:

1. 0.0020mm
2. 0.0040mm
3. 0.14mm
4. 0.55mm

Reference:-

Page no :48 · The elongation of an object is: · d = FL/AY

Where F is the force, L is the length, A is the cross-sectional area, and L is the modulus of elasticity (Young's modulus). D or del L is obviously the elongation.

Be sure your units are correct for doing this, because they need to cancel out to get a final unit of just meters. You want newtons, meters, square meters, and newtons/m^2.

d = (5000 * 5)/(3.14*0.34^2 * 125*10^8) · d = 5.5*10^-6 m · d = 0.0055 mm

So it will elongate 0.0055 mm. I Since D is closest, but is off by 100 times, I suspect that for the Young's modulus, you meant 1.25*10^8, not 125*10^8. I would choose option D.

Q4. A particle oscillating in simple harmonic motion is: (1 marks)

1. never in equilibrium because it is in motion
2. never in equilibrium because there is always a force
3. in equilibrium at the ends of its path because its velocity is zero there
4. in equilibrium at the center of its path because the acceleration is zero there

Q5. In simple harmonic motion, the restoring force must be proportional to the: (1 marks)

1. amplitude
2. frequency
3. velocity
4. displacement page no:44

Reference:- Now we have a restoring force that is proportional to the distance away from the equilibrium point

Q6. A 160-N child sits on a light swing and is pulled back and held with a horizontal force of 100 N. The magnitude of the tension force of each of the two supporting ropes is: (1 marks)

1. 60N
2. 94N
3. 120N