STA100 Midterm Past Papers Set 4
- Type
- Midterm past paper
- Course
- STA100 General Mathematics and Biostatistics
- Size
- PDF 649 KB
- Updated
- 23 Oct 2026
You get 3 free files a day on the website. Add the Chrome extensionSign in with the extension for 30 a day.
Preview text
Text from pages 2, 3, 4 of 7. Download the file for all 7 pages.
- 4[2 0 ] 4 −1
3) If b2-4ac<zero then there will be No Solution
Subjective
Q1. You have 5 chess cards named A,B,C,D,E . In how many ways you can arrange them to make a word from them (in this question we have to find possible number of permutations ) (2 marks)
5! = 5×4×3×2×1 = 120
Q2. Find the exact value of Cos150 without using calculator. (3 marks)
Cos( 1800-Cos300)
By applying angle rule
Cos[ 2(90))0-Cos300]
-Cos(-300)
-Cos30 0 = - √3
Q3. If f(x)=4x+1 and g(x)=x-6 then find f(x)-g(x). (2 marks)
f.g(x)= (4x+1)(x-6)
f.g(x)= (4x2-22x-6)
Q4. Write the equation in complete square form , x2 +4x+2 . (3 marks)
x2 +bx+ b +2b
x2 +bx+ 16 +24
x2 +4x+ 16 +2-(2) ( 4 ) 0 ] −4 [ 8 x2 +4x+4 (x+2)2
5) .(2-4i)(3+5i)
2(3+5i)-4i)(3+5i)
6+10i-12i-20i2
6-2i-20(-1)
6-2i+20
26-2i
6) .a=3000, r=
2 find the a10
2(3+5i)-4i)(3+5i)
.a=3000, r= 2 find the a10 = a1r10-1
a10 = (3000)(r9)
a
10 = (3000)( )
a
3000 10 = (
Q7. A club has five seniors and three junior players . For and upcoming tournament they have to make a team of two juniors and two seniors. how many possible number of teams they can make (this question is from combinations ) (5 marks)
rP = 2P = 2! = 2! = 2∗1 = 2 = 2 s 2–2! 0! 0!
8) If f(x)= 3x-1 and g(x)= 2x-1 then find the product of i.e, f.g(x)
f.g(x)= (3x-1)(2x-1)
f.g(x)= [6x2-5x+1]
Same method will be used as above;
10) Expand the Sin(A-B)
Sin(A-B) = (SinA+(-B)) Sin(A-B) = SinA+Cos(-B) + CosA+Sin(-B) Sin(A-B) = SinA+Cos(B) + CosA+Sin(-B) Sin(A-B) = SinA+CosB - CosA+SinB
11) Write down the properties to reduce a metric to reduce echelon form. Definition:
“A matrix is in echelon form if it has the following properties” o Every non-zero row begins with a 1 (called a leading 1) o Every leading one in a lower row is further to the right of the leading one above it. o If there are zero rows, they are at the end of the matrix
Example; [0 1 2]
Definition:
A matrix is in reduced echelon form if in addition to the above three properties it also has the following property: o Every other entry in a column containing a leading one is zero
Example; [0 1 0]
Q12. If Z=2-Bi find out Z.Z*=?
Z=2-Bi Z*=2+Bi Then, Z.Z*= (2-Bi)( 2+Bi) Z.Z*= [2(2)+1(Bi)-Bi(2)-Bi(Bi)] Z.Z*= [4+Bi-2Bi-Bi2] Z.Z*= [4+(1-2)B-B(-1)] Z.Z*= [4+(-1)B+B] Z.Z*= [4-B+B] Z.Z*= 4
Q13. What is the cardianality of Sets?
A= {a,b,c,d,……,z}
Caridanility of set A is |A|= 26
B= {0,±1, ±2, ±3,…..}
(Set B is a infinite there for its caridanility can’t be counted) Caridanility of set B is |B|= is uncountable
C= {4,6}
Caridanility of set C is |C|= 2
Related STA100 files
All STA100 files →Get more out of VUBuddy, for free
- Unlimited downloads
- The explanation behind every MCQ answer
- Study offline on slow data
- 30 downloads a day instead of 3
- Sign in and buy Pro Semester here
One Pro Semester membership works in both the extension and the app.