STA301 Midterm Solved MCQs Set 3 by Junaid

STA301 Midterm Solved MCQS By Junaid

Statistics and Probability (Virtual University of Pakistan)

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STA301 Midterm Solved MCQS By Junaid

Statistics and Probability (Virtual University of Pakistan)

Scan to open on Studocu

Studocu is not sponsored or endorsed by any college or university pg. 1 A histogram is consisting of a set of a set of adjacent rectangle whose bases are marked off by:

a. Class boundaries (Lecture no 4 Page no 32 Handouts)

b. Class limits c. Class frequency d. Class marks

The middle value of an ordered array of numbers is the

a. Mean

b. Median (Lecture no 7 Page no 59 Handouts)

c. Mode d. Midpoint

If Mean =25 & S.D is 5 then C.V is:

a. 100%

b. 20% (Lecture no 11 Example Page no 88 Handouts)

c. 10% d. 25%

Solution: C.V = (S.D/X) x 100 = (5/25) x 100 = 20% Answer

you connect the mid-points of rectangles in a histogram by a series of lines that also touches the x-axis from both ends, you will get:

a. Ogive b. Frequency polygon

c. Frequency curve page 38

d. Historigram

The conditional probability P (A/B) is:

a. P (A n B)/P (B) (Lecture no 20 Page no 154 Handouts)

b. P (A n B)/P (A) c. P (A U B)/P (B) d. P (A U B)/P (A)

Serious disadvantage of using range as a measure of dispersion is that it is based on only:

a. Minimum Values b. Maximum Values c. Both Minimum and Maximum values

d. None of the above

pg. 2 Frequency of a variable is always in:

a. Fraction form b. Percentage form c. Less than form

d. Integer form

5C5 is equal to

a. 5

b. 1

c. 10 d. 24

Chebychev’s inequality does not hold for k = ?

1. 3
2. 2
3. 1
4. 0 (Lecture no 12 Page no 94 Read CHEBYCHEV’S THEOREM)

Correct answer: 0 (Lecture no 12 Page no 94 Read CHEBYCHEV’S THEOREM)

If A = {1,2,3,4} and B = {3,4,5,6} then A – B will be:

a. {1,2}

b. {3,4} c. {3,2,1} d. {1,2,3,4,5,6}

If P (B|A) = 0.25 and P (A and B) = 0.20, then P (A) is

a. 0.05

b. 0.80

c. 0.95 d. 0.75

Solution: P (B|A) = [P (A and B)] / P (A) P (A) = [0.20 / P (B|A)] P (A) = [0.20 / 0.25]

P (A) = 0.80

According to Empirical rule, approximately 68% of the measurements will fall within:

a. (Mean - S.D, Mean + S.D) (Lecture no 12 Page no 90 Handouts)

b. (Mean - 2S.D, Mean + 2S.D) c. (Mean - 3S.D, Mean + 3S.D)